If it's not what You are looking for type in the equation solver your own equation and let us solve it.
27q-q^2+400=0
We add all the numbers together, and all the variables
-1q^2+27q+400=0
a = -1; b = 27; c = +400;
Δ = b2-4ac
Δ = 272-4·(-1)·400
Δ = 2329
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$q_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$q_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$q_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(27)-\sqrt{2329}}{2*-1}=\frac{-27-\sqrt{2329}}{-2} $$q_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(27)+\sqrt{2329}}{2*-1}=\frac{-27+\sqrt{2329}}{-2} $
| 3+5(6-7b)=-107 | | -16x^2+5x+20=0 | | 4^x-6.2^x+8=10 | | 0.35x+0.25(20-x)=6.00 | | y=1/4+24×-2 | | 0.45x+0.05(4-x)=1.00 | | 7(v-8)+24=-8.857142857(v-6) | | 14=0.33x+6 | | -6(4+6b)=-96 | | (x+5)3=x | | 178=5(5-4v)-7 | | 5r+2=11-7r | | 5a-2(a-3)=2a+10 | | 2b+6=4b-5 | | 7t+3+2t=0 | | 7t+3+2t=15 | | 8-2b=-2(b=-2(b=-3;b=5) | | 3k-7=3 | | 264=14-y | | x-0.2x=3.40 | | 2r-3.1=1.8 | | 79=4v | | 0.02222222222x+0.025=1 | | -1/6d+2/3=1/4d-1/2 | | 3^(x+5)=15 | | 83=-2x+3(5x-7) | | 2(4+2k)=10=k | | 1/45x+1/40x=1 | | 10x+14=0 | | x/5+4x=180 | | 3y^2-17y-28=0 | | (8/11)=(3/2y) |